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steposvetlana [31]
2 years ago
12

Grace is looking at a report of her monthly cell-phone usage for the last year to determine if she needs to upgrade her plan. Th

e list represents the approximate number of megabytes of data Grace used each month.
700, 735, 680, 890, 755, 740, 670, 785, 805, 1050, 820, 750
Mathematics
1 answer:
Sav [38]2 years ago
7 0

If the value of mean is 781.67, then the standard deviation will be 100. Then the correct option is C.

The complete question is given below.

Grace is looking at a report of her monthly cell-phone usage for the last year to determine if she needs to upgrade her plan. The list represents the approximate number of megabytes of data Grace used each month.

700, 735, 680, 890, 755, 740, 670, 785, 805, 1050, 820, 750

What is the standard deviation of the data? Round to the nearest whole number.

65

75

100

130

<h3>What is a standard deviation?</h3>

It is a metric for statistical information dispersion. The degree of spread indicates how much the result varies.

Grace is looking at a report of her monthly cell-phone usage for the last year to determine if she needs to upgrade her plan.

The list represents the approximate number of megabytes of data Grace used each month.

700, 735, 680, 890, 755, 740, 670, 785, 805, 1050, 820, 750

The mean of the data will be

Mean = (700 + 735 + 680 + ...... + 820 + 750) / 12

Mean = 781.67

Then the standard deviation will be

SD² = [(700 – 781.67)² + (735 – 781.67)² + ..... + (750 – 781.67)²] / 12

SD² = 10072.2222

SD = 100.36 ≈ 100

Then the correct option is C.

More about the standard deviation link is given below.

brainly.com/question/12402189

#SPJ1

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Researchers have noted a decline in cognitive functioning as people age (Bartus, 1990). However, the results from other research
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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

Yes the researcher can  conclude that the supplement has a significant effect on cognitive skill

b

d =  0.5778

c

The result of this hypothesis test shows that there is sufficient evidence to  that the supplement had significant effect.The measure of effect size is  large due to the large value of Cohen's d (0.5778 > 0.30 )

Step-by-step explanation:

From the question we are told that

  The sample size is  n=16

    The sample mean is  M  =  50.2

    The standard deviation is \sigma  = 9

    The  population mean is  \mu =  45

     The level of significance is  \alpha =  0.05

The null hypothesis is H_o  \mu =45

The alternative hypothesis is H_a  \mu \ne 45

Generally the test statistics is mathematically represented as

          z =  \frac{M -  \mu}{\frac{\sigma}{\sqrt{n} } }

=>       z =  \frac{50.2 - 45}{\frac{9}{\sqrt{16} } }

=>       z =  2.31

Generally the p-value is mathematically represented as

     p-value  =  2 *  P(Z >  z )

      p-value  =  2 *  P(Z >  2.31 )

From the z-table  

      P(Z >  2.31 ) = 0.010444

=>     p-value  =  2 *  0.010444

=>     p-value  =  0.021

From the obtained values we see that p-value <  0.05

 Decision Rule

 Reject the null hypothesis

Conclusion

There is sufficient evidence to conclude that the supplement has a significant effect on the cognitive skill of elderly adults

Generally the Cohen's d for this study is mathematically represented as

    d =  \frac{M  -  \mu}{\sigma }

=>  d =  \frac{50.2 -45}{9 }

=>  d =  0.5778

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Answer:

Add up the area of all the sides

Step-by-step explanation:

Surface area is the shell of a 3d shape, not the volume so you add the outside of the shape.

Hope this helps! :)

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