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Katyanochek1 [597]
2 years ago
8

Solve the following quadratic by completing the square. y = x2 - 6x +2

Mathematics
1 answer:
Nana76 [90]2 years ago
4 0

Answer: 3 \pm \sqrt{7}

Step-by-step explanation:

1) \text{ } x^{2}-6x+2=0\\\\2) \text{ } x^{2}-6x=-2\\\\3) \text{ } x^{2}-6x+\left(\frac{-6}{2} \right)^{2}=-2+\left(\frac{-6}{2} \right)^{2}=7\\\\4) \text{ } (x-3)^{2}=7\\\\5) \text{ } x-3 =\pm \sqrt{7} \longrightarrow \boxed{3 \pm \sqrt{7}}

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Vertical angles are congruent. Two nonadjacent angles formed by two intersecting lines are vertical angles.
Gnesinka [82]

Answer:

A

Step-by-step explanation:

If two nonadjacent angles formed by two intersecting lines = Vertical angles= congruent

Then

Two non adjacent angles formed by two intersecting lines are congruent

4 0
3 years ago
Read 2 more answers
Of a group of randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wa
Wittaler [7]

Answer:

We are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%

Step-by-step explanation:

We are given that in a group of randomly selected adults, 160 identified themselves as executives.

n = 160

Also we are given that 42 of executives preferred trucks.

So the proportion of executives who prefer trucks is given by

p = 42/160

p = 0.2625

We are asked to find the 95% confidence interval for the percent of executives who prefer trucks.

We can use normal distribution for this problem if the following conditions are satisfied.

n×p ≥ 10

160×0.2625 ≥ 10

42 ≥ 10 (satisfied)

n×(1 - p) ≥ 10

160×(1 - 0.2625) ≥ 10

118 ≥ 10 (satisfied)

The required confidence interval is given by

$ p \pm z\times \sqrt{\frac{p(1-p)}{n} } $

Where p is the proportion of executives who prefer trucks, n is the number of executives and z is the z-score corresponding to the confidence level of 95%.

Form the z-table, the z-score corresponding to the confidence level of 95% is 1.96

$ p \pm z\times \sqrt{\frac{p(1-p)}{n} } $

$ 0.2625 \pm 1.96\times \sqrt{\frac{0.2625(1-0.2625)}{160} } $

$ 0.2625 \pm 1.96\times 0.03478 $

$ 0.2625 \pm 0.06816 $

0.2625 - 0.06816, \: 0.2625 + 0.06816

(0.1943, \: 0.3306)

(19.43\%, \: 33.06\%)

Therefore, we are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%

5 0
4 years ago
Please help me i dont get either one of them i just need one of them. Please shiw steps. Thanks
pychu [463]

NO.4:X=38

NO.5:X=41

NO.6:X=24

5 0
3 years ago
Please help.. the third and fourth choice are the same as the first two but positive
LenaWriter [7]

Answer:

Your answer is going to be one of the 1/3 I'm pretty sure it is the positive 1/3 because the line is not decreasing.

Step-by-step explanation:

4 0
3 years ago
Two planes left an airport at noon. One flew east at a certain speed and the other flew west at twice the speed. The planes were
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The plane flying west was flying at 600 miles per hour and the plane flying east was flying 300 miles per hour
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4 years ago
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