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2 years ago

In the given figure, ΔABC is a right triangle.

Mathematics

1 answer:

ch4aika [34]2 years ago

5 0

The true statement about right-angle triangle ABC is that: A. sin(A) = cos(C) and cos(A) = sin(C).

<h3>How to apply basic trigonometry?</h3>

In order to determine the angles, we would apply basic trigonometry. From the diagram of the right-angled triangle shown below, we can deduce the following parameters:

Angle (θ) = 45°.

Opposite (Opp) side = a.

Hypotenuse (Hyp) = c.

Adjacent (Adj) side = b.

By applying the basic trigonometry functions, we have:

sin(A) = Opp/Hyp = a/c.

sin(C) = Opp/Hyp = c/b.

cos(A) = Adj/Hyp = c/b.

cos(C) = Adj/Hyp = a/c.

From the above, we can logically deduce that sin(A) is equal to cos(C) and cos(A) is equal to sin(C).

Read more on sine trigonometry here: brainly.com/question/20367642

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A family has two cars. The first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of

professor190 [17]

The fuel consumption of each of the cars during the week are as follows;

The first car consumes 20 gallons of fuel.

The second car consumes 30 gallons of fuel.

Reasons:

Fuel efficiency of the first car = 15 miles per gallon

Fuel efficiency of the second car = 35 miles per gallon

Combined distance traveled by the two cars in a week = 1,350 miles

The total gas consumption during the week = 50 gallons

Let x represent the number of gallons consumed by the first car, and let y

represent the number of gallons consumed by the second car, we get the

following system of simultaneous equations;

15·x + 35·y = 1,350...(1)

x + y = 50...(2)

Therefore;

y = 50 - x

Which gives;

15·x + 35 × (50 - x) = 1,350

15·x + 1,750 - 35·x = 1,350

1,750 - 1,350 = 35·x - 15·x = 20·x

400 = 20·x

x = 400 ÷ 20 = 20

The number of gallons consumed by the first car, x = 20 gallons

From equation (2), we have;

x + y = 50

y = 50 - x

Therefore;

y = 50 - 20 = 30

The number of gallons consumed by the second car, y = 30 gallons

Learn more about word problems that lead to simultaneous equations here:

brainly.com/question/1717365

6 0

1 year ago

Once again... we almost finish, solve for x

algol13

Answer:

x = 34

Step-by-step explanation:

Angles are supplementary:

x + 7 + 4x + 3 = 180

5x + 10 = 180

5x = 170

x = 34

3 0

2 years ago

A rectangular pool is 30 1/3 feet long and 12 1/2 feet wide. What is the area of the pool?

butalik [34]

About 379.1666666666666
The 6 is repeating. Or about 379 if your rounding.

4 0

3 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

Write an equation to find the number. Solve. Twenty-four less than 4 times a number is equal to 30 more than -2 times the number

Amanda [17]

4x - 24 = -2x + 30

4x + 2x = 30 + 24
6x = 54
x = 9

answer: the number is 9

5 0

3 years ago

Read 2 more answers