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kati45 [8]
2 years ago
7

Find a₁0 given that a7 = 6 and d = 3 in the arithmetic sequence.

Mathematics
1 answer:
levacccp [35]2 years ago
7 0

The tenth term of the arithmetic sequence will be 15. Then the correct option is A.

<h3>What is the arithmetic sequence?</h3>

Let a₁ be the first term and d is the common difference between the terms. Then the nth term will be given as

\rm a_n = a_1 + (n - 1)d

We have

a₇ = 6

d = 3

n = 7

Then the first term will be

a₇ = a₁ + (7 – 1)3

6 = a₁ + 18

a₁ = 6 – 18

a₁ = -12

Then the 10th term will be

a₁ = -12

d = 3

n =10

Then we have

a₁₀ = -12 + (10 – 1)3

a₁₀ = -12 + 27

a₁₀ = 15

Then the tenth term of the arithmetic sequence will be 15.

Then the correct option is A.

More about the arithmetic sequence link is given below.

brainly.com/question/15412619

#SPJ1

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And using a calculator, excel ir the normal standard table we have that:

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And we can calculate the probability like this:P(-1.5 \leq Z \leq 1.5) = P(zStep-by-step explanation:

A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the probability that the sample mean is in the interval 47<=X<53. Is the assumption of normality important. Why?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(50,12)  

Where \mu=50 and \sigma=12

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:

P(-1.5 \leq Z \leq 1.5) = P(z

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