Answer:

Step-by-step explanation:
<u>Given Data:</u>
Base area =
= 108 in.²
Volume = V = 729 in.³
<u>Required:</u>
Height = h = ?
<u>Formula:</u>

<u>Solution:</u>
For h, rearranging formula:
![\displaystyle h = \frac{V}{A_{B}} \\\\h =\frac{729 \ in.^3}{108 \ in.^2} \\\\h = 6.75 \ in.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%20%3D%20%5Cfrac%7BV%7D%7BA_%7BB%7D%7D%20%5C%5C%5C%5Ch%20%3D%5Cfrac%7B729%20%5C%20in.%5E3%7D%7B108%20%5C%20in.%5E2%7D%20%5C%5C%5C%5Ch%20%3D%206.75%20%5C%20in.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer: bro its the last one
Step-by-step explanation:
Answer:
Step-by-step explanation:
ABC and DEF are parallel lines. So, ∠ABE and ∠BED are co interior angles.
∠ABE + ∠BED = 180 {SUM OF CO INTERIOR ANGLE IS 180}
∠ABE+ 110.2 = 180
∠ABE = 180 - 110.2
∠ABE = 69.8
Now, ABC is straight line
∠ABE + ∠EBG + ∠CBG = 180
69.8 + ∠EBG + 34.8 = 180
104.6 + ∠EBG = 180
∠EBG = 180 - 104.6
∠EBG = 75.4
Again, DEF is straight line
∠DEB + ∠BEG + ∠GEF = 180
110.2 + ∠BEG + 25.6 = 180
∠BEG + 135.8 = 180
∠BEG = 180 - 135.8
∠BEG = 44.2
In triangle BEG,
∠BEG + x + ∠EBG = 180 { sum of all angles of triangle is 180}
44.2 + x + 75.4 = 180
x + 119.6 = 180
x = 180 - 119.6
x = 60.4
The first option because turn them all into degrees and it says:
54, 60, 90, 120, 255
You know that d = 100 and w = 125, so you plug that into the equation and solve as shown:
b= 100 + d - w
= 100 + 100 - 125
= 200 - 125
= $75
You now have $75 left as balance.