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2 years ago

May I have some assistance please

1 answer:

7 0

The method that can be used to write the equation of a line in slope-intercept form given two points is option A.

<h3>Calculations and Parameters</h3>

When a person wants to write the equation of a line in slope-intercept form given two points, he would have to:

Know the two points
Use them to find the slope
You would get the value of m
Use it to solve the equation y= mx + b
Find the y-intercept

Therefore, the answer is option A.

Read more about slope-intercept here:

brainly.com/question/1884491

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Figure CDEF is a parallelogram.

NikAS [45]

Answer:

n=10, CF=59, FE=49

6 0

3 years ago

Read 2 more answers

How is the series 5+11+17…+251 represented in summation notation?

NISA [10]

Answer:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

Step-by-step explanation:

Given:

Series 5+11+17+...+251

To find:

Summation notation of the given series

Summation Notation:

$\displaystyle \large{\sum_{k=1}^n a_k}$

Where n is the number of terms and $\displaystyle \large{a_k}$ is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

Arithmetic Series

A series that has common difference.

Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

11-5 = 6
17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

Arithmetic Sequence

$\displaystyle \large{a_n=a_1+(n-1)d}$

Where $\displaystyle \large{a_n}$ is the nth term, $\displaystyle \large{a_1}$ is the first term and $\displaystyle \large{d}$ is the common difference:

So for our general term:

$\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}$

And for number of terms, substitute $\displaystyle \large{a_n}$ = 251 and solve for n:

$\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}$

Now we can convert the series to summation notation as given the formula above, substitute as we get:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

5 0

3 years ago

Plz help I will mark you brainlist plz help

lakkis [162]

Answer

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Step-by-step explanation:

*Hope this helped*

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3 years ago

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Function 1 is defined by the following table

AnnyKZ [126]

Wjats the best way for you yetwywtw you get your help for your work and work on the building your new job and you can do more homework and your help with the help for help with the family room and your family member and family members are coming now

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2 years ago

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Nitella [24]

Answer:

noestiendo

Step-by-step explanation:

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