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gizmo_the_mogwai [7]
2 years ago
15

What else would need to be congruent to show that triangle ABC is congruent to triangle DEF by ASA?

Mathematics
1 answer:
kykrilka [37]2 years ago
6 0

BC = EF

the side has to lie between the two angles

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6. The vertices of ALMN are L(7,4), M(7,16), and
max2010maxim [7]

Answer:

(a) LM=12 units, LN=35 units, MN=37 units

(b)8 84 units

(c) 210 square units

Step-by-step explanation:

(a)

Since points L and M have same x coordinates, it means they are in the same plane. Also, since the Y coordinates of L and N are same, they also lie in the same plane

Length LM=\sqrt {(7-7)^{2}+(16-4)^{2}}=12 units

Length LN=\sqrt {(42-7)^{2}+(4-4)^{2}}=35 units

LengthMN=\sqrt {(42-7)^{2}+(4-16)^{2}}=37 units

Alternatively, since this is a right angle triangle, length MN is found using Pythagoras theorem where

MN=\sqrt {(LN)^{2}+(LM)^{2}}=\sqrt {(12)^{2}+(35)^{2}}=37 units

Therefore, the lengths LM=12 units, LN=35 units and MN=37 units

(b)

Perimeter is the distance all round the figure

P=LM+LN+MN=12 units+35 units+37 units=84 units

(c)

Area of a triangle is given by 0.5bh where b is base and h is height, in this case, b is LN=35 units and h=LM which is 12 units

Therefore, A=0.5*12*35= 210 square units

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3 years ago
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andrew11 [14]

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Step-by-step explanation:

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Answer:

3/4 or .75

Step-by-step explanation:

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3(y-1)=y-11

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-1.5

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