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3 years ago

The perimeter of a rectangle is 40 feet. If the length is 15 feet, 6 inches ; what is the width

Mathematics

1 answer:

Natali5045456 [20]3 years ago

4 0

Answer:

4 feet 6 inches

Step-by-step explanation:

P=2(l+w) [the addition of all sides of the rectangle]

P = 40'

L = 15’6”

So, 40' = 2 (15’6’ + w)

40' = 31’ + 2w

9' = 2w

4’6” = w

If it's easier you can break it change feet into inches and then change back to feet.

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What multiplies to be 280 and adds to be negative 36

photoshop1234 [79]

The two numbers are -18+ 2√(11) and -18 -2√(11).

-18+ 2√(11)+ [-18 -2√(11)]= -36
[-18+ 2√(11)]* [-18 -2√(11)]= 280.

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3 years ago

part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.

andreev551 [17]

Answer: $\bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}$

Step-by-Step Explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: (15)² + (3√11)² = hypotenuse² → hypotenuse = 18

$6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}$

Note: 8² + 15² = hypotenuse² → hypotenuse = 17

$7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}$

Note: hypotenuse not needed for tan

$8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}$

Note: 2² + 6² = hypotenuse² → hypotenuse = 2√10

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3 years ago

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2 years ago

Above are two different models of the same triangular-shaped garden. If the height of the model on the left is 14 cm, what is th

Katyanochek1 [597]

Please consider the attached graph.

We have been given that there are two different models of the same triangular-shaped garden. The height of the model on the left is 14 cm. We are asked to find the height of the model.

First of all, we will convert 14 cm into feet.

We can see that model on left side has a scale of 1 cm is equal to 15 feet.

14 cm = 14×15 feet = 210 feet.

We can see that model on the right side has a scale of 1 cm is equal to 7.5 feet.

Since both models represent same triangular-shaped garden, so the actual height for the both models will be same.

Now we need to convert actual height of 210 feet into inches using 2nd scale.

$\text{210 ft}=210\text{ ft}\times \frac{1\text{ inch}}{\text{7.5 ft}}=\frac{210}{7.5}\text{ inch}=28\text{ inch}$

Therefore, the height of the model on right is 28 inches.

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3 years ago

The perimeter of a rectangle is 40 feet. If the length is 15 feet, 6 inches ; what is the width​

The perimeter of a rectangle is 40 feet. If the length is 15 feet, 6 inches ; what is the width