A combination lock has a code consisting of 3 numbers, each of which can be 0 to 39, with numbers repeated. Jillian says that th
2 answers:
Answer:
Jillian is not correct
Jillian has summed up the possible number of codes for each digit instead of multiplying it
Step-by-step explanation:
The lock has a code that consists of 3 number
It is given that the number in the lock code can be used between to
Thus, out of total set of numbers (i.e
), the numbers can be repeated.
This means for all three code numbers the opportunity of choosing a number is same i.e. between
Now, the first digit of the code can be any number between
Like wise the second and third digit of the code can be any number between
Thus. the possible number of codes with repetition allowed are
Hence, Jillian is not correct
Jillian has summed up the possible number of codes for each digit instead of multiplying it
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Answer:
The degrees of freedom are given by:
The p value would be given by:
Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60
Step-by-step explanation:
Information given
60, 56, 60, 55, 70, 55, 60, and 55.
We can calculate the mean and deviation with these formulas:
Replacing we got:
represent the mean
represent the sample standard deviation for the sample
sample size
represent the value that we want to test
represent the significance level
t would represent the statistic
represent the p value
Hypothesis to test
We want to test if the true mean is less than 60, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic would be given by:
(1)
Replacing the info we got:
The degrees of freedom are given by:
The p value would be given by:
Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60