2 years ago

Given: FB ║ CG ∠BFE and ∠C are supplementary. Prove CA ║ FE

Mathematics

1 answer:

Alina [70]2 years ago

5 0

Answer:

Step-by-step explanation:

1) $FB \parallel CG$ , $\angle BFE$ and $\angle C$ are supplementary (given)

2) $\angle ABF \cong \angle C$ (corresponding angles theorem)

3) $\angle BFE$ and $\angle ABF$ are supplementary (supplements of congruent angles are congruent)

4) $CA \parallel FE$ (converse of the same-side interior angles theorem)

You might be interested in

if your ans is correct i will choose you as a brainlist when the number of student of a school was increased by 30% it became 45

kicyunya [14]

Step-by-step explanation:

find 30% of 455

which is = 136.5

then subtract 136.5 from the original number(455)

455 - 136.5

=318.5 student

6 0

3 years ago

Read 2 more answers

Lines AB and CD intersect at P. PR is perpendicular to line AB, and the measure of ∠APD is 170°. A series of intersecting lines.

Anna [14]

Answer:

A) $10^0$

Step-by-step explanation:

Please see the attached file:

7 0

4 years ago

Which line , or solid , is the best line of best fit ? What evidence can you provide to prove this is the best line of best fit

lubasha [3.4K]

Line 1 because it is line one ☝️

5 0

3 years ago

Find a ratio that is equlvant (4)/(11)

DedPeter [7]

Answer:

8/22, 16/44, etc

Step-by-step explanation:

.................

6 0

3 years ago

In Triangle DEF, the sum of the measures of Angle D and Angle E is 110. The sum of the measures of Angle E and Angle F is 150. F

nevsk [136]

Answer:

<D + <F = $100^{o}$

Step-by-step explanation:

Given: <D + <E = $110^{o}$

<E + <F = $150^{o}$

But, the sum of angles in a triangle = $180^{o}$ .

Thus;

<D + <E + <F = $180^{o}$

$110^{o}$ + <F = $180^{o}$

⇒ <F = $180^{o}$ - $110^{o}$

= $70^{o}$

<F = $70^{o}$

Also,

<E + <F = $150^{o}$

<E + $70^{o}$ = $150^{o}$

<E = $150^{o}$ - $70^{o}$

= $80^{o}$

<E = $80^{o}$

So that;

<D + <E = $110^{o}$

<D + $80^{o}$ = $110^{o}$

<D = $110^{o}$ - $80^{o}$

= $30^{o}$

<D = $30^{o}$

⇒ <D = $30^{o}$ , <E = $80^{o}$ , and <F = $70^{o}$ .

Therefore;

<D + <F = $30^{o}$ + $70^{o}$

= $100^{o}$

8 0

3 years ago