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Rama09 [41]
2 years ago
13

On a coordinate plane, a graph shows Street on the x-axis and Avenue on the y-axis. A line is drawn from Tia to Lei. Tia is at (

4, 8) and Lei is at (12, 20).
Tia lives at the corner of 4th Street and 8th Avenue. Lei lives at the corner of 12th Street and 20th Avenue. The fruit market is Three-fourths the distance from Tia’s home to Lei's home.

x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1

y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1

Where is the fruit market?

6th Street and 11th Avenue
10th Street and 17th Avenue
9th Street and 15th Avenue
8th Street and 14th Avenue
Mathematics
1 answer:
natali 33 [55]2 years ago
7 0

Answer:

The Fruit market is at -  6th Street and 11th Avenue

Step-by-step explanation:

Distance is a numerical measurement of how far apart objects or points are. to find the distance between two points is the length of the line segment connecting them we use distance formula.

for example :-

if (x, y) and (p, q) are the two points joining the line segment then distance between them is given by the formula :-

\sqrt{(p- x)^2 + (q-y)^2} this is known as the distance formula.

using the above formula :

distance between points (4, 8)  and (12, 20) is:

\sqrt{(12-4)^2 + (20-8)^2}

√(8² + 12²)

√208

14.42

Now the fruit market is Three-fourths the distance between Tia’s home to Lei's home.

therefore,

3/4×14.42  = 10.8

now we can check that option (A ) i.e. (6, 11)  distance from lei home i.e. (12, 20) is equal to 10.8

hence the fruit market is at the = 6th Street and 11th Avenue

learn more about the distance formula at :

brainly.com/question/20881088

#SPJ10

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Step-by-step explanation:

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How can percents describe a change in area?
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3 years ago
Which multiplication expression is eqeul to 3/5 ÷ 1/2
eduard

Answer:

Lets solve = 3/5 ÷ 1/2

3/5 ÷ 1/2

= 3/5 × 2/1

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In mixed fraction its

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____________________

Now lets solve "a" option

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8 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

6 0
3 years ago
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