Equal because these numbers are of the same value
So to work this out we need to find the 4th root of each of those and pick the one that gives an integer.
A:
![\sqrt[4]{1.6*10^1^1} = 632.455...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E1%7D%20%3D%20632.455...)
This is a decimal therefore <em>not</em> an integer.
B:
![\sqrt[4]{1.6*10^1^2} =1124.682...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E2%7D%20%3D1124.682...)
Again a decimal, therefore <em>not </em>an integer.
C:
![\sqrt[4]{1.6*10^1^3} =2000](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E3%7D%20%3D2000)
This is a whole number, so it <em>is </em>an integer.
D:
![\sqrt[4]{1.6*10^1^4} =3556.558...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E4%7D%20%3D3556.558...)
Decimal, therefore <em>not </em>an integer
E:
![\sqrt[4]{1.6*10^1^5} =6324.555...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E5%7D%20%3D6324.555...)
Again a decimal, <em>not</em> an integer.
The only one that gives an integer when put to the 4th root is C, therefore:
could be A^4, as the 4th root of it is an integer.
I'll do a similar problem, and I challenge you to do this using similar techniques!
If John works for 15$ a hour with his friends rather than working for 20$ an hour for 50 hours a month, what's the monthly opportunity cost?
John would make 20*50=1000 dollars a month at the second option as he makes 20$ an hour 50 times. Next, if he works with his friends, he makes 15*50=750 dollars as he works 50 hours for 15 dollars an hour, or adds 15 50 times.
His opportunity cost would be <highest money>-<lowest money>=1000-750=250 dollars a month. Good luck on this question, and feel free to ask further questions!
Hi there
3(p + q) = q
Solve for P
Use the distributive property
(3)(p) + (3)(q) = q
3p + 3q = q
3p = q-3q
3p = -2q
p = -2q/3
The answer is D
If you have any further questions please let me know :)