Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the eq
uation below as a model:
1 answer:
The radical equation that has an extraneous solution is 5✓x + 10 - 15 = 30
<h3>How to calculate the equation?</h3>
Based on the information given, the radical equation that has an extraneous solution is 5✓x + 10 - 15 = 30.
This will be:
5✓x + 10 - 15 = 30
Collect like terms
5✓x = 30 - 10 + 15
5✓x = 35
✓x = 35/5
✓x = 7
x = 7² = 49
The equation that does not have an extraneous solution will be ✓x + 1 + 7 = 4. Here, ✓x = -4 and has no solution.
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