Question

F(x)=12(x-10)2+18 What is the "a" value of this function?

Answer 1

Answer:

12

Step-by-step explanation:

Assuming that the 2  actually represents square, the equation is
$f(x) = 12(x-2)^2 + 18$

$(x-2)^2 = x^2 - 4x + 4\\\\12(x-2)^2 + 18 = 12( x^2 - 4x + 4) + 18 = 12x^2 -48x + 48 + 18 = 12x^2 -48x + 66$

This equation is of the form
$ax^2 + bx + c$

$a = 12, b = -48, c = 66$

Note

Since the question is only asking for the a value which is the coefficient of x² it is clear that 12 is the coefficient without expanding (x-2)² but it is always better to proceed as above in case you are asked for b and c values also

Answer 2

Value of the function at x=a is $12a^{2} -240a +1218$.

Given function f(x)=$12(x-10)^{2} +18$

We have to find the value of function at x=a.

For this we have to just put x=a in the function f(x)=$12(x-10)^{2}+18$

f(a)=12$(a-10)^{2} +18$

we have to expand (x-10) to the power 2  to get the value of  function.

f(a)=$12(a^{2} +10^{2} -20a)+18$

=$12a^{2}+1200-240a+18$

=$12a^{2} -240a+1218$

Hence the value of function at x=a is $12a^{2} -240a+1218$ means f(a)=$12a^{2} -240a+1218$.

Learn more about functions at brainly.com/question/10439235

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