The conditions which must be met to use z procedures in a significance test about a population proportion include:
I. The population is greater than 10 times the sample size.
II. The probability of success multiplied by the sample size is greater than or equal to 10.
III. The probability of failure multiplied by the sample size is greater than or equal to 10.
<h3>What is Z procedure?</h3>
This is a statistical test done on data that follows a normal distribution and determines if the population means are different when the variances are known and the sample size is large.
The population must be greater than 10 times the sample size in this scenario with the other appropriate conditions being mentioned above.
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Step-by-step explanation:
Hope it will help you.
Answer:
Step-by-step explanation:
Half of the 16 oz = 8 oz of peanuts.
2 oz are almonds.
1 oz is cashews.
3 oz are raisins.
So, we know 8+2+1+3 = 14 oz of stuff in detail.
We're told the rest is chocolate chips, which means 16 - 14 = 2 oz.
BUT always read the question.
It does not ask the weight of the chocolate chips. It asks the fraction.
That is
2/16 = 1/8
It’s equals x=1 hope that helps
Add the zeros on to 7.5 to which you would move the decimal and it should be like this 750.0 or 750
