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zhenek [66]
2 years ago
5

In a plane, line b is parallel to line f, line f is parallel to line g, and line h is perpendicular to line b.

Mathematics
1 answer:
ehidna [41]2 years ago
8 0

The statement that cannot be true is that g cannot be parallel to h (g ║h)

<h3>How  to know parallel lines in a plane?</h3>

On the plane ,

line b is parallel to line f.

Therefore,

b ║ f

line f is parallel to line g,

Therefore,

f ║ g

line h is perpendicular to line b.

h ⊥ b

Therefore,

Since line h is perpendicular b, line b is perpendicular to h.

b can be parallel to g on the plane.

g cannot be parallel to h because h is perpendicular to b.

h can be perpendicular to f because b is parallel to f.

learn more parallel lines here: brainly.com/question/3443478

#SPJ1

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Vesnalui [34]
F=kma
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a=\frac{f}{km}
6 0
3 years ago
Simplify answer without parenthesis<br> (6w)
sertanlavr [38]

Answer:

6w

Step-by-step explanation:

You can't simplify it any further:

6 * w

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<u>6w</u>

6 0
2 years ago
If a concrete column is 6 inches by 6 inches square and 8 ft. long, calculate its weight in Newtons, given a specific weight of
tangare [24]
<h2>Weight of column is 555.83 N</h2>

Step-by-step explanation:

Size of column = 6 inch x 6 inch x 8 ft

Size of column = 0.5 ft x 0.5 ft x 8 ft

Volume of column = 0.5 x 0.5 x 8 = 2 ft³

Specific weight of concrete = 62.4 lb/ft³

Mass = Volume x Specific weight

Mass = 2 x 62.4

Mass = 124.8 lb = 124.8 x 0.454 = 56.66 kg

Weight = 56.66 x 9.81 = 555.83 N

Weight of column is 555.83 N

7 0
3 years ago
PLZZ ANSWER ILL GIVE YOU BRAINLYIST
Monica [59]

Answer:

29.4 (B)

Step-by-step explanation:

<u>First, get rid of parentheses by multiplying.</u>

5(3 1/5 + 2 4/5) = 16 + 14 = 30.

Subtract 0.6

30 - 0.6 = 29.4

4 0
3 years ago
Which of the following groups of terms can be used interchangeably when working with normal distributions?
BARSIC [14]

Answer:

The correct answer is D) areas, probability, and relative frequencies

Step-by-step explanation:

This is because each of these terms refers to an amount of space surrounding the mean on the normal distribution curve. Each of them let's us know how likely a spot is to have a value within it.

The z-score would not fit this as it identifies the value and how far away a single spot on the graph would be.

5 0
3 years ago
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