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wolverine [178]
1 year ago
13

Using the quadratic formula to solve 5x = 6x²-3, what are the values of x?

Mathematics
1 answer:
Salsk061 [2.6K]1 year ago
8 0

Answer:

\boxed{\sf{x =  \frac{5 \pm \sqrt{97} }{12} }}

Step-by-step explanation:

\sf{5x = 6 {x}^{2} - 3 }

\sf{0 = 6 {x}^{2} - 3 - 5x }

\sf{0 = 6 {x}^{2} - 5x - 3 }

  • a = 6
  • b = - 5
  • c = - 3

\sf{x =  \frac{ - b \pm \sqrt{ {b}^{2}  - 4ac} }{2a} }

\sf{x =  \frac{ - ( - 5) \pm \sqrt{ { - 5}^{2}  - 4(6)( - 3)} }{2(6)} }

\sf{x =  \frac{5 \pm \sqrt{ 25   + 72} }{12} }

\sf{x =  \frac{5 \pm \sqrt{97} }{12} }

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