Question

Using the quadratic formula to solve 5x = 6x²-3, what are the values of x?

Answer 1

Answer:

$\boxed{\sf{x = \frac{5 \pm \sqrt{97} }{12} }}$

Step-by-step explanation:

$\sf{5x = 6 {x}^{2} - 3 }$

$\sf{0 = 6 {x}^{2} - 3 - 5x }$

$\sf{0 = 6 {x}^{2} - 5x - 3 }$

• a = 6
• b = - 5
• c = - 3

$\sf{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }$

$\sf{x = \frac{ - ( - 5) \pm \sqrt{ { - 5}^{2} - 4(6)( - 3)} }{2(6)} }$

$\sf{x = \frac{5 \pm \sqrt{ 25 + 72} }{12} }$

$\sf{x = \frac{5 \pm \sqrt{97} }{12} }$