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Maslowich
2 years ago
8

A plane takes off from an airport on a bearing of 270° and travels at a speed of 320 mph. after sometime and flight, space the p

lane encounters a 35 mph wind blowing directly north. Find the speed of the airplane after it encounters the wind.
A.322mph B.330mph C.285mph D.355mph
Mathematics
1 answer:
ratelena [41]2 years ago
8 0

The speed of the plane after it encounters the wind is C.285mph

<h3>How to calculate the speed of the plane when it encounters the wind?</h3>

Since the plane takes off from an airport on a bearing of 270° and travels at a speed of 320 mph it's velocity is v = (320cos270°)i + (320sin270°)j

= (320 × 0)i + (320 × -1)j

= 0i - 320j

= - 320j mph

Also, the plane encounters a 35 mph wind blowing directly north. The velocity of the wind is v' = 35j mph

So, the velocity of the plane after it encounters the wind is the resultant velocity, V = v + v'

= -320j mph + 35j mph

= -285j mph

So, the speed of the plane after it encounters the wind is the magnitude of V = |-285j| mph

= 285 mph

So, the speed of the plane after it encounters the wind is C.285mph

Learn more about speed of plane here:

brainly.com/question/3387746

#SPJ1

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