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dezoksy [38]
2 years ago
13

Write a program to print each item in the list of your favourite ice cream. please give proper answers. ​

Computers and Technology
1 answer:
timama [110]2 years ago
5 0

Answer:

Python

Explanation:

#List Favorite ice-cream

ice_cream = ["Pistachio", "Cookies and cream", "Chocolate", "Banana split" , "Vanilla"]

for flavor in ice_cream:

print(flavor)

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Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server
sattari [20]

Answer:

The smallest number of servers required is 3 servers

<em />

Explanation:

Given

Reliability = 99.98\%

Individual Servers = 95\%

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

p = 95\%\\

It should be noted that probabilities always add up to 1;

So,

p + q = 1'

Subtract p from both sides

p - p + q = 1 - p

q = 1 - p

Substitute p = 95\%\\

q = 1 - 95\%

Convert % to fraction

q = 1 - \frac{95}{100}

Convert fraction to decimal

q = 1 - 0.95

q = 0.05

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

p = 99.98\%

Recall that probabilities always add up to 1;

So,

p + q = 1

Subtract q from both sides

p + q - q = 1 - q

p = 1 - q

So,

p = 1 - q = 99.98\%

1 - q = 99.98\%

Let the number of servers be represented with n

The above expression becomes

1 - q^n = 99.98\%

Convert percent to fraction

1 - q^n = \frac{9998}{10000}

Convert fraction to decimal

1 - q^n = 0.9998

Add q^n to both sides

1 - q^n + q^n= 0.9998 + q^n

1 = 0.9998 + q^n

Subtract 0.9998 from both sides

1 - 0.9998 = 0.9998 - 0.9998 + q^n

1 - 0.9998 = q^n

0.0002 = q^n

Recall that q = 0.05

So, the expression becomes

0.0002 = 0.05^n

Take Log of both sides

Log(0.0002) = Log(0.05^n)

From laws of logarithm Loga^b = bLoga

So,

Log(0.0002) = Log(0.05^n) becomes

Log(0.0002) = nLog(0.05)

Divide both sides by Log0.05

\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}

\frac{Log(0.0002)}{Log(0.05)} = n

n = \frac{Log(0.0002)}{Log(0.05)}

n = \frac{-3.69897000434}{-1.30102999566}

n = 2.84310893421

n = 3 (Approximated)

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0
3 years ago
Who plays warzone im a roze sweat and ill try to carry with loadout
alexira [117]

Answer:

I type play warzone- If u wanna add me my user is Chachee_Girl. Dont ask- and im on ps5

8 0
2 years ago
Which is the best description of a hierarchical report?
mixas84 [53]

Answer:

d

Explanation:

a report with records sorted in ascending order is the right answer

6 0
3 years ago
Convert infix to postfix
kvv77 [185]

Answer:

static int checkSymbol(char ch)

{

switch (ch)

{

case '+':

case '-':

return 1;

case '*':

case '/':

return 2;

case '^':

return 3;

}

return -1;

}

static String convertInfixToPostfix(String expression)

{

String calculation = new String("");

Stack<Character> operands = new Stack<>();

Stack<Character> operators = new Stack<>();

 

for (int i = 0; i<expression.length(); ++i)

{

char c = expression.charAt(i);

if (Character.isLetterOrDigit(c))

operands.push(c);

else if (c == '(')

operators.push(c);

 

else if (c == ')')

{

while (!operators.isEmpty() && operators.peek() != '(')

operands.push(operators.pop());

 

if (!operators.isEmpty() && operators.peek() != '(')

return NULL;    

else

operators.pop();

}

else

{

while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))

operands.push(operators.pop());

operators.push(c);

}

}

while (!operators.isEmpty())

operands.push(operators.pop());

while (!operands.isEmpty())

calculation+=operands.pop();

calculation=calculation.reverse();

return calculation;

}

Explanation:

  • Create the checkSymbol function to see what symbol is being passed to the stack.
  • Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
  • Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
  • While the operators is  not empty, keep pushing the character to the operators stack.
  • At last reverse and return the calculation which has all the results.
4 0
3 years ago
How would you maximize the use of outsourced programmers?
Lerok [7]

Answer:

the answer is: release them when the project is complete

Explanation:

8 0
3 years ago
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