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Airida [17]
2 years ago
12

A cyclist traveled kilometers per hour faster than an in-line skater. In the time it took the cyclist to travel kilometers, the

skater had gone kilometers. Find the speed of the skater.
Mathematics
1 answer:
anzhelika [568]2 years ago
8 0

The speed of skaters was 10 km per hr.

<h3>How to solve? </h3>

Mathematically, the speed of an object is directly proportional to the distance traveled and inversely proportional to the time taken. In simple words, the more the speed, the distance traveled is more in a short period and vice-versa.

Let the speed of the skater be x

We know, speed = \frac{Distance}{Time}

According to the question:

\frac{20}{x} = \frac{40}{x + 10}

Cross multiplying both sides,

20(x+10) = 40x

20x + 200 = 40x

20x = 200

x = 10

Thus, the speed of skaters was 10 km per hr.

To know more about Speed-distance questions visit:

brainly.com/question/4931057

#SPJ4

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Step-by-step explanation:

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Help please <br> I need to pass my class
valina [46]

Answer:

look below

Step-by-step explanation:

thing to note:

sin = opposite/hypotenuse

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3 0
3 years ago
Which of the values shown are potential roots of f(x) = 3x3 â€"" 13x2 â€"" 3x 45? Select all that apply.
Verdich [7]

The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

And the accurate root is 3 it can be determined by using rules of the rational root equation.

<h2>Given that,</h2>

Function; \rm f(x) = 3x^3 - 13x^2 -3x + 45

<h3>We have to determine,</h3>

Which of the values shown are potential roots of the given equation?

<h3>According to the question,</h3>

Potential roots of the polynomial are all possible roots of f(x).

\rm f(x) = 3x^3 - 13x^2 -3x + 45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

\rm p=\dfrac{All\  the \ positive}{Negative\  factors \ of\  45}

\rm q=\dfrac{All\  the \ positive}{Negative\  factors \ of\  3}

The factor of the term 45 are,

\pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45

And The factor of 3 are,

\pm1, \ \pm3

All the possible roots are,

\dfrac{p}{q} = \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

Now check for all the rational roots which are possible for the given function,

\rm f(x) = 3x^3 - 13x^2 -3x + 45\\\\ f(1) = 3(1)^3 - 13(1)^2 -3(1) + 45 = 3-13-3+45 = 32\neq 0\\\\ f(-1) = 3(-1)^3 - 13(-1)^2 -3(-1) + 45 =- 3-13+3+45 = 32\neq 0\\\\ f(3) = 3(3)^3 - 13(3)^2 -3(3) + 45 = 81-117-9+45 =0\\\\ f(-3) = 3(-3)^3 - 13(-3)^2 -3(-3) + 45 = -81+117+9+45 =-144\neq 0

Therefore, x = 3 is the potential root of the given function.

Hence, The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}.

For more details about Potential roots refer to the link given below.

brainly.com/question/25873992

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Answer:

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Step-by-step explanation:

This is because this is how you get the circumference.

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