Question

Triangle ADB, point C lies on segment AB and forms segment CD, angle ACD measures 90 degrees. Point A is labeled jungle gym and point B is labeled monkey bars.
Beth is planning a playground and has decided to place the swings in such a way that they are the same distance from the jungle gym and the monkey bars. If Beth places the swings at point D, how could she prove that point D is equidistant from the jungle gym and monkey bars?

answer choices
If segment DC bisects segment AB, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.
If segment DC bisects segment AB, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.
If segment AD bisects segment AB, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.
If segment AD bisects segment AB, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.

Answer 1

She can prove that point D is equidistant from the jungle gym and monkey bars is A. If segment DC bisects segment AB, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.

What is the Perpendicular Bisector Theorem?

The perpendicular bisector theorem simply states that any point on the perpendicular bisector is simply equidistant from both the endpoints of the line segment on which it is drawn.

Therefore, we can see that given triangle ADB and the segments it forms, if Beth places her playground at equidistance from the jungle gym and monkey bars, then she can prove that point D is equidistant from the jungle gym and monkey bars is If segment DC bisects segment AB, then point D is equidistant

Read more about perpendicular bisector theorem here:

brainly.com/question/18840179

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