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Lana71 [14]
2 years ago
14

4= 3/7(3x+14) Solve for x in simplest form.

Mathematics
2 answers:
KengaRu [80]2 years ago
8 0

  • \large{ \boxed{ \tt{ x =  \frac{ - 14}{9} }}}

- Please see the attached picture for full solution!:)

------------- HappY LearninG <3 ---------

makvit [3.9K]2 years ago
4 0
The above answer is correct! Just took and got correct
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Flura [38]
The answer would be 6
7 0
3 years ago
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3. The scale of a model car is 1:32.
Jlenok [28]

Answer: The answer would be 73.6

Step-by-step explanation: We have to 32x2.3 to get 73.6.

Hope this helps!

3 0
3 years ago
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Hola me podrían ayudar por favor. Convertir las fracciones a decimales y ubicar a los decimales en la recta numérica. a. 2/3 b.
NISA [10]

Answer:

Step-by-step explanation:

a decimal

2/3 = 0.7

8/5 = 1.6

-5/2 = -2.5

7/4 = 1.8

9/2 =  4.5

-11/3 = -3.7

13/5 = 2.6

-7/4 = -1.8

Esto es solo un bosquejo del número, usando un gráfico, use 0.1 para una unidad en la recta numérica.

-  ________________________________________________________ +

  |    |     |      |     |       |      |       |     |     |     |    |       |     |     |      |     |     |       |            

-5  -4 -3.7  -3 -2.5  -2  -1.8   -1    0  0.7  1   1.6  1.8  2   2.6   3   4   4.5   5

8 0
3 years ago
A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa
yarga [219]

Answer:

z= \frac{85-70}{10}=1.5

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

Our student: Final exam score = 85; Class: M = 70; SD = 10.

His friend: Final exam score = 45; Class: M = 35; SD = 5.

The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

E(X)= \mu =70, SD_X=\sigma=10  

The z score is given by:

z=\frac{x-\mu}{\sigma}

If we use this we got:

z= \frac{85-70}{10}=1.5

Let Y the random variable that represent the scores for his friend, and for this case we know that:

E(Y)= \mu =35, SD_Y=\sigma=5  

The z score is given by:

z=\frac{y-\mu}{\sigma}

If we use this we got:

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

3 0
3 years ago
Please help im really confused :(​
pantera1 [17]

Answer:

a) π

b) 33.4

Step-by-step explanation:

C = πd

1) substitute 105 for C: 105 = πd

2) plug in approximate value of 3.14 for π: 105 = (3.14) d

3) isolate to solve for d: 105/3.14 = d

4) simplify: 105/3.14 ≈ 33.4

5 0
3 years ago
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