Question

In 1898, L. J. Bortkiewicz published a book called The Law of Small Numbers, where using data he collected for twenty years, he showed that the number of soldiers killed by horse kicks each year in the Prussian army followed a Poisson distribution with a mean of 0.61. What is the probability that there will be exactly three deaths in two years?
hurry please will pick brainly and step by step appreacite it

Answer 1

Answer:

given : 0.61 per year

formula poisson probability : p(x=k)=xke-x/k!

(a) The parameter λ is the product of the rate per year and the number of years. The number of years is 1 year in this case.

λ=0.61×1=0.61

Evaluate the formula of the Poisson probability at k=0,1:

P(X=0)= 0!

(0.61)

0

e

−0.61

​

≈0.5434

P(X=1)=

1!

(0.61)

1

e

−0.61

​

≈0.3314

Add the corresponding probabilities:

P(X≤1)=P(X=0)+P(X=1)=0.5434+0.3114=0.8748

Use the complement rule:

P(X>1)=1−P(X≤1)=1−0.8748=0.1252

Note: The solution in the back of the book is the probability of at least one death instead of more than 1 death, thus the solution in the back of the book is not correct.

Step-by-step explanation:

this is prob wrong so im sorry in advance!