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faltersainse [42]
3 years ago
6

Complete the factorization of 3x2 – 5x 2. which two factors can be multiplied together to make this trinomial?

Mathematics
1 answer:
EastWind [94]3 years ago
7 0

The two factors multiplied together to make a trinomial is (x-1)(3x-2).

Given equation is 3x²-5x+2.

An algebraic equation which of the second degree in x is known as quadratic equation. The quadratic equation in its standard form is ax2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.

In the given equation,

Multiply the first coefficient 3 with the last coefficient 2  so we get 2×3=6

Use any two numbers which on multiply give 6 and on adding or subtracting give -5.

Such two numbers are -2 and -3

On multiplying, (-3)×(-2)=6

On Adding, -3-2=-5

So, break -5x into -3x and -2x and we get

3x²-3x-2x+2

Taking out 3x common from the first two terms and -2 from the last two terms as

3x(x-1)-2(x-1)

Taking out the common term (x-1) as common and get

(x-1)(3x-2)

Hence, the two factors of the equation 3x²-5x+2 that can be multiplied together to make this trinomial is (x-1)(3x-2).

Learn more about factorization from here brainly.com/question/22673662

#SPJ4

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Elina [12.6K]
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Multiply the numerator as well as the denominator by the same number. Therefore its like multiplying by 1.
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Quotient of 5/3 ÷5/7
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5 0
4 years ago
4 times the sum of 7 and 3 is subtracted from 41​
Montano1993 [528]

Answer:

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7 0
4 years ago
The television show Found has been successful for many years. That show recently had a share of 19, meaning that among the TV se
sergiy2304 [10]

Answer:

a) 0.0523 = 5.23%

b) 0.9477 = 94.77%

c) 0.2242 = 22.42%

d) YES

Step-by-step explanation:

This situation could be modeled with a binomial distribution where

The probability of getting exactly k “successes” in n trials is given by  

P(X=k)=\binom{n}{k}p^k(1-p)^{n-k}

Where p is the probability of “success”.

In this case we can assume that “success” is the fact that the household interviewed is tuned to Found.  

So, p=0.19 and n = 14 (the households interviewed).

a)

The probability that none of the households are tuned to Found is P(X=0)

P(X=0)=\binom{14}{0}0.19^0(0.81)^{14}=0.0523=5.23\%

b)

The probability that at least one household is tuned to Found is  

1- P(X=0) = 1-0.0523 = 0.9477 = 94.77%

c)

The probability that at most one household is tuned to Found is  P(X=0)+P(X=1)

P(X=0)+P(X=1)=0.0523+\binom{14}{1}0.19^1(0.81)^{13}=0.2242=22.42\%

d)

According to this sample, the probability that more than one household is tuned to Found would be 100%-22.42% = 77.58%, so it does appear that the 19% share value is wrong.

3 0
4 years ago
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