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mrs_skeptik [129]
2 years ago
10

On a coordinate plane, a line goes through (negative 2, negative 4) and (2, 2). a point is at (negative 3, 1). what is the equat

ion, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)? y – 1=negative three-halves(x 3) y – 1=negative two-thirds(x 3) y – 1= two-thirds(x 3) y – 1= three-halves(x 3)
Mathematics
1 answer:
S_A_V [24]2 years ago
3 0

The equation, in point-slope form, of the line that is parallel to the given line and passes through the point is y - 1 = 3/2(x+3)

<h3>Equation of a line</h3>

A line is the distance between two points. The equation of a line in point-slope form is expressed as:

y - y0 = m(x-x0)

Given the coordinates (-2, -4) and (2, 2) on the line, the slope is expressed as:

Slope = 2-(-4)/2-(-2)

Slope = (6)/4

Slope = 3/2

Find the equation of the line

y -(1) = 3/2(x-(-3))

y - 1 = 3/2(x+3)

Hence the equation, in point-slope form, of the line that is parallel to the given line and passes through the point is y - 1 = 3/2(x+3)

Learn more on equation of the line here: brainly.com/question/18831322

#SPJ1

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insens350 [35]

The confidence interval for the difference p1 - p2 of the population proportion is (0.063, 0.329)

<h3>How to determine the confidence interval?</h3>

The given parameters are:

n₁ = 93; n₂ = 80

p₁ = 0.814;  p₂ = 0.618

The critical value at 95% confidence interval is

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CI = (p_1 - p_2) \pm z * \sqrt{\frac{p_1(1  - p_1}{n_1} + \frac{p_2(1 - p_2)}{n_2}}

Substitute known values in the above equation

CI = (0.814 - 0.618) \pm 1.96 * \sqrt{\frac{0.814 * (1  - 0.814)}{93} + \frac{0.618 * (1 - 0.618)}{80}}

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CI = (0.196 - 0.133, 0.196 + 0.133)

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7 0
2 years ago
What is the radius of a circle with the equation x^2+y^2+6x-2y+3?
atroni [7]

Answer:

r = √13

Step-by-step explanation:

Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms:  x^2 + 6x            + y^2 -2y             = 3.  Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."  

We need to "complete the square" of x^2 + 6x.  I'll just jump in and do it:  Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x:     x^2 + 6x  + 3^2 - 3^2.  Then do the same for y^2 - 2y:  y^2 - 2y + 1^2 - 1^2.

Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2.  Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1.  Making these replacements:

(x + 3)^2 - 9 + (y - 1)^2 -1 = 3.  Move the constants -9 and -1 to the other side of the equation:  (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13

Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r:  r^2 = 13, so that the radius is r = √13.


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