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2 years ago

7

What is the 10th term for sequence 4; 8; 13; 19; 26

1 answer:

Mariana [72]2 years ago

3 0

Answer:

40

Step-by-step explanation:

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the product of five consecutive odd integers is 945 what is the greatest possible value of any of these integers

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If 945 is the product of 5 CONSECUTIVE ODD numbers, let's find the prime factors of 945:

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When asked to factor the trinomial x^2-16x+64, a student gives the answer (x – 8)(x + 8). Which of the following statements is t

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Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2

r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

$\frac{21}{128}$

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