Question

Solve x2 – 8x = 3 by completing the square. Which is the solution set of the equation?

Answer 1

Answer:

$(4-\sqrt{19},4+\sqrt{19)$

Step-by-step explanation:

we have

$x^{2} -8x=3$

Divide the coefficient of term x by 2

$-8/2=-4$

Squared the number

$(-4)^2=16$

Adds the number 16 to the both sides

$x^{2} -8x+16=3+16$

$x^{2} -8x+16=19$

Rewrite as perfect squares

$(x-4)^{2}=19$

take square root both sides

$(x-4)=(+/-)\sqrt{19}$

$x=4(+/-)\sqrt{19}$

$x_1=4(+)\sqrt{19}$

$x_2=4(-)\sqrt{19}$

therefore

The solution set is

$(4-\sqrt{19},4+\sqrt{19)$

Answer 2

Answer:

its A

Step-by-step explanation: