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1 year ago

Show work, can someone help me out having trouble with this problem

Mathematics

1 answer:

Over [174]1 year ago

7 0

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: f = \cfrac{9}{a}+7$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \:a = \cfrac{9}{f - 7}$

$\qquad \tt \rightarrow \:a(f - 7) = 9$

$\qquad \tt \rightarrow \:(f - 7) = \cfrac{9}{a}$

$\qquad \tt \rightarrow \:f = \cfrac{9}{a} + 7$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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Please help with all nor one otherwise you will be reported . Show and explain all your work

Vitek1552 [10]

37. Volume: l×w×h
38. Volume: (pi)r^2×h
39. Volume: (1/2b×h)×l

37. l=4
w=4
h=6

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16×6= 96ft^3

38. (pi)=3.14
r=5
h=12

(3.14×5^2)×12
(3.14×25)×12
78.5×12= 942in^3

38. b=4
h=3
l=8

(1/2×3×4)×8
(1/2×12)×8
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3 years ago

The body weight of a healthy 3 month-old colt should be about μ = 60 kg. (Source: The Merck Veterinary Manual, a standard refere

tatuchka [14]

Answer:

The null hypothesis will be $H_o : \mu = 60 \ kg$

The alternative hypothesis will be $H_a : \mu < 60$

The alternative hypothesis will be $H_a : \mu > 60$

The alternative hypothesis will be $H_a : \mu \ne 60$

left; right; both

Step-by-step explanation:

Considering question a

The body weight of the colt is $\mu = 60 \ kg$

The null hypothesis will be $H_o : \mu = 60 \ kg$

Considering question b

Given that we want to test the claim that the average weight of a wild Nevada colt is less than 60 kg , then

The alternative hypothesis will be $H_a : \mu < 60$

Considering question c

Given that we want to test the claim that the average weight of such a wild colt is greater than 60 kg , then

The alternative hypothesis will be $H_a : \mu > 60$

Considering question d

Given that we want to test the claim that the average weight of such a wild colt is different from 60 kg , then

The alternative hypothesis will be $H_a : \mu \ne 60$

Considering question e

For question b , the corresponding p-value will be on the left because the average weight is less than 60 kg

For question c , the corresponding p-value will be on the right because the average weight is more than 60 kg

For question d , the corresponding p-value will be on both because the average weight is different from 60 kg

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2 years ago

Bo and Erica are yoga instructors. Between the two of them, they teach 45 yoga classes each week. If Erica teaches 15 fewer than

Solnce55 [7]

Answer:

20 and 25.

Step-by-step explanation:

Given:

They both teach total 45 yoga classes each week.

Erica teaches 15 fewer than twice as many as Bo.

To find:

How many classes does each instructor teach per week = ?

Solution:

Let number of classes are taken by Bo = $x$

Then number of classes are taken by Erica = $2x - 15$ (given)

Total number of classes are taken by both = 45 (given)

According to the question.

$x$ + $2x - 15$ = 45

$3x - 15 = 45$

By adding both side by 15

$3x = 60\\$

By dividing both side by 3

$x = 20$

number of classes are taken by Bo = $x$ = 20

number of classes are taken by Erica = $2x - 15$

= $2\times20 - 15 = 40- 15 = 25\\$

Therefore, number of classes are taken by Bo and Erica is 20 and 25.

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3 years ago

Simplify the following expression.

levacccp [35]

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Hey yall like dat sweet algeba? then 5ab - 2c where a = 2 b = 3 and c is 0. gud luck daddio

nordsb [41]

Answer:

Step-by-step explanation:

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3 years ago