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tiny-mole [99]
3 years ago
7

The graph of the piecewise function f(x) is shown.

Mathematics
2 answers:
iris [78.8K]3 years ago
6 0
1. The range of a function is the set of all values that f can produce for all the x-es in the domain.

2. If we are given the graph, in order to find the range, we project the graph into the y axis. Informally, we draw the "shadow" of the graph into the y axis as in the FIGURE atached.

3. The range is <span>D || {y | −5 ≤ y ≤ −1}</span>

Anna [14]3 years ago
3 0

Hello the range is d

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please choose the correct answer, i will upvote all your comments! look at triangle stu: a right triangle stu is shown with the
Nata [24]
Since this is a right triangle, we can just use Pythagorean Theorem to solve for the side SU:

Length of Hypotenuse^2 = Length of First Leg^2 + Length of Second Leg^2
SU^2 = ST^2 + TU^2
SU = sqrt(ST^2 + TU^2)
SU = sqrt(42^2 + 56^2)
SU = sqrt(4900)
SU = 70

Therefore, the answer is is 70 centimeters.
6 0
3 years ago
Read 2 more answers
5 hundreds 6 ten thousands 2 ones
dolphi86 [110]
The anwser is 526  because u have 5 hundreds and u have 6 ten thousands 2 ones  

8 0
3 years ago
Read 2 more answers
What is true for: y = 13(x - 4)2 - 4
notka56 [123]

Answer:

y=78

Step-by-step explanation:

y=13(x-4) 2-4

y=(13-52) -2

y=(-24+104)

y=78

7 0
3 years ago
What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
3 years ago
I need help I don’t understand
lara [203]

you'll first need to understand the symbols, I've attched a cheat sheet :)

you'll need to see if AB is linked to CD reversed.

If not then it's not A

For B you'll have to see if the angles are parralel to each other.

and for C you'll have to see if the angles are the same.

and D is the same as C

so the answer is ab=cd

<h2>now you understand :)</h2>

4 0
3 years ago
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