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hjlf
2 years ago
13

Hey sample has a sample proportion of .3 which sample size will produce the widest 95% confidence interval when estimating the p

opulation parameter
Mathematics
1 answer:
Alex777 [14]2 years ago
3 0

The sample size which will produce sample proportion of 0.3 and 95% confidence interval is 36.

Given sample proportion of 0.3, confidence level 95%.

A confidence interval of proportions is given by:

π±z\sqrt{}π(1-π)/n

In which :

π is the sample proportion,

z is the critical value

n is the sample size.

Margin of error=z\sqrt{}π(1-π)/n

z value for confidence level of 95% is 1.96

Margin of error=1.96\sqrt{0.3*0.7/n}

The widest interval has the highest margin of error, since the margin of error and since the margin of error is inversely proportional to the sample size , a lower sample size generates a higher margin of error.

Hence sample size which is correct is 36.

Learn more about margin of error at brainly.com/question/24289590

#SPJ4

Question is incomplete as it also includes options like:

a)46

b)68

c)56

d)36.  

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