Answer:
The Miami Dolphins had 3 touchdowns and 3 field goals.
Step-by-step explanation:
It is given that During their last game, the Miami Dolphins scored 6 times, for a total score of 30 points. They scored 7 points for each touchdown and 3 points for each field goal.
We need to write and solve the system of equations to find the total touchdowns and field goals scored.
Let x represents the number of touchdowns.
Let y be the number of field goals.
It is given that the Miami Dolphins scored 6 times
....(1)
They scored 7 points for each touchdown and 3 points for each field goal.
The total score is 30 points:
...(2)
Put the value of x from equation (1) into equation (2).
Put y = 3 in equation 1.
Hence, the Miami Dolphins had 3 touchdowns and 3 field goals.
41.625 feet long because it is the product of 4 5/8*9
Answer:
Step-by-step explanation:
dtttttttttbccccccccccisssssssserrrrrrrrr774444444444
SOLUTION
This is a binomial probability. For i, we will apply the Binomial probability formula
i. Exactly 2 are defective
Using the formula, we have
Note that I made the probability of being defective as the probability of success = p
and probability of none defective as probability of failure = q
Exactly 2 are defective becomes the binomial probability
Hence the answer is 0.1157
(ii) None is defective becomes
hence the answer is 0.4823
(iii) All are defective
(iv) At least one is defective
This is 1 - probability that none is defective
Hence the answer is 0.5177
Ok so any number tat makes the denomenator 0 or makes the inside of a square root negative is restricted
we only have a denomenaor so
100v=0
v=0
therefor 0 is the excluded value since 0/0 doesn't make sense