Question

X^2/0.35-x=1.3*10^-5 Solve for x

Answer 1

The solution to the value of x in the given equation is x = 0.00212658 or x = -0.00213958

Solving algebraic equations:

The process of solving the unknown value of an algebraic equation involves equating the values of the unknown to the constant value.

Given that:

$\mathbf{\dfrac{x^2}{0.35-x}= 1.3 \times 10^{-5} }$

$\mathbf{x^2 = 1.3 \times 10^{-5} (0.35-x) }$

x² = 4.725 × 10⁻⁶ - 1.3 × 10⁻⁵x

= $x^2 + 1.3\times10^{-5}x - 4.725 \times 10^{-6}$

= x²+0.000013x-0.000004725

• Solving for (x) by using the quadratic equation:

x = 0.00212658 OR x = -0.00213958

Learn more about quadratic equations here:

brainly.com/question/776122

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