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pantera1 [17]
2 years ago
7

3 red balls, 4 white balls, and 1 green ball are in a bag. Balls are drawn without replacement. Find the probability that the re

d balls can be drawn before the green ball is drawn.
Mathematics
1 answer:
jolli1 [7]2 years ago
7 0

The probability that the red balls can be drawn before the green ball is drawn is 3/8.

<h3>What is Probability?</h3>

The probability is the measure of the likelihood of an event to happen.

Given:

red balls= 3

white balls = 4

green balls = 1

So, Probability of red balls

=3/8

Probability of green balls

=1/7

Learn more about probability here:

brainly.com/question/14546377

#SPJ1

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MariettaO [177]

The average daily balance after 20 days is; $1750

<h3>Average Balance</h3>

The initial balance after grace period is; $25,000

Afterwards, A payment of $5,000 each is made on the 10th and 20th day.

Hence, the total balance after 20 days is;

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3 years ago
Which term is a perfect square of the root 3x4?<br>​
KiRa [710]

Answer:

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Step-by-step explanation:

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The first two numbers in a sequence h are h(1) = 2 and h(2) = 6.
Ghella [55]

Answer:

Step-by-step explanation:

Given the first two numbers of a sequence as 2, 6...

If it is an arithmetic difference, the common difference will be d = 6-2 = 4

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d is the common difference = 4

n is the number if terms

Substituting the given values in the formula.

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2) If the sequence us a geometric sequence

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r is the common ratio

r is gotten by the ratio of the terms I.e

r = T2/T1

r = 6/2

r = 3

Since a = 2

Tn = 2(3)^(n-1)

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There could be collinear but need to be on the same plane
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