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pantera1 [17]
2 years ago
7

3 red balls, 4 white balls, and 1 green ball are in a bag. Balls are drawn without replacement. Find the probability that the re

d balls can be drawn before the green ball is drawn.
Mathematics
1 answer:
jolli1 [7]2 years ago
7 0

The probability that the red balls can be drawn before the green ball is drawn is 3/8.

<h3>What is Probability?</h3>

The probability is the measure of the likelihood of an event to happen.

Given:

red balls= 3

white balls = 4

green balls = 1

So, Probability of red balls

=3/8

Probability of green balls

=1/7

Learn more about probability here:

brainly.com/question/14546377

#SPJ1

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vladimir1956 [14]

The solution is x < 3.

Solution:

The given expression is 3x + 4 < 13.

To solve the given inequality.

3x + 4 < 13

Subtract 4 tiles on both sides of the inequality.

⇒ 3x + 4 – 4 < 13 – 4

⇒ 3x < 9

Divide by 3 tiles on both sides of the inequality.

⇒ \frac{3x}{3} =\frac{9}{3}

⇒ x < 3

Hence the solution is x < 3.

4 0
3 years ago
at the library, you find 9 books on a certain topic. the librarian tells you that 55% of the books on this topic have been signe
e-lub [12.9K]
Multiply 9 books by 55% by doing

9 x .55 = 4.95

We can't have 4.95 books, though so it rounds down to 4 because you can't just add another .05.
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3 years ago
Help a bab out please?
Volgvan

Answer:

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Step-by-step explanation:

5 0
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enyata [817]

Step-by-step explanation:

Dave + 6 friends = 7 friends in total

84 ÷ 7 = 12

Each friend paid $12

4 0
3 years ago
The system with one and only one solution set is called a/an system
beks73 [17]

Answer:

Consistent and Independent System

Step-by-step explanation:

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