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Mathematics

1 answer:

dalvyx [7]1 year ago

7 0

Matching each equation of the plecewise function represented in the graph will be:

2 < x < 3 = 3 - x
0 < x < 2 = 1
x = 2 = x
3 < x < 5 = 5 - x

<h3>How to illustrate the information?</h3>

It should be noted that a domain simply means the set of inputs that are accepted by the function.

In this case, the equation of the piecewise function represented is given.

The graph is attached.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

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There are 15 female performers in a dance recital. The ratio of men to women is 2:3. How many men are in the dance recital?

andre [41]

If 3 represents women, then we divide 15 by 3 to get 5. once we have 5, we must then multiply 2 and 5. once that is done we have 10. So the number of men in the dance recital is 10.

Hope this answer helps! feel free to ask any additional questions :)

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3 years ago

In a survey from 1998, 449 teenagers were surveyed about the music that they listen to. Of these teenagers, 129 of them said tha

marshall27 [118]

Answer:

H0:p1=p2; Ha:p1≠p2, which is a two-tailed test.

Step-by-step explanation:

We formulate our hypotheses as

H0:p1=p2; Ha:p1≠p2, which is a two-tailed test.

Supposing the probability or proportion of the first survey is equal to the probability or proportion of the second survey. This will be the null hypothesis and the alternative hypotheses would be that these two proportions or probabilities are unequal.

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2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :