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2 years ago

Write the equation of the line that passes through the point (-8,-3) with : slope of -1/4

Mathematics

1 answer:

viktelen [127]2 years ago

8 0

Answer:

In slope-intercept form:

$y = - \frac{1}{4} x - 5$

In standard form:

$x + 4y = - 20$

Step-by-step explanation:

$- 3 = - \frac{1}{4} ( - 8) + b$

$- 3 = 2 + b$

$b = - 5$

$y = - \frac{1}{4} x - 5$

$- 4y = x + 20$

$- x - 4y = 20$

$x + 4y = - 20$

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Solve the system of linear equations by graphing y = -4x + 2 ; y = -x - 1 <br> What is the solution?

elena-s [515]

Answer:

Step-by-step explanation:

Easiest way would be to substitute points into the given equations and plot your answers.

E.g. if you substitute points into your first equation you get:

If x = 0, y = -4(0) +2 = 2

If x = 1, y = -4(1) +2 = -2

If x = -1, y = -4(-1) +2 = 6

Etc.

Second equation:

If x = 0, y= -(0) -1 = -1

If x = 1, y = -1 -1 = -2

If x = -1, y = -(-1) -1 = 0

Pretty much just plug in values for x into the equations to find y.

Once you have your points, draw a line :)

Where the two lines intercept would be the solution.

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3 years ago

Solve for x: 1 over 3 (2x − 8) = 4. (1 point)

garik1379 [7]

Answer:

x=6

Step-by-step explanation:

$2x - 8 = 4 \\ 2x = 4 + 8 \\ 2x = 12 \\ x = \frac{12}{2} \\ x = 6$

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2 years ago

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3 years ago

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aalyn [17]

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3 years ago

Read 2 more answers

A set of exam scores is normally distributed and has a mean of 80.2 and a standard deviation of 11. What is the probability that

ZanzabumX [31]

Answer:

93.32% probability that a randomly selected score will be greater than 63.7.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 80.2, \sigma = 11$