Question

A certain field is a rectangle with a perimeter of 1030 feet. The length is 181 feet more than the width. Find the width and length of the rectangular field.

Answer 1

Step-by-step explanation:

the perimeter is

2×length + 2×width = 1030 ft

length + width = 515 ft

length = width + 181

now we use that in the first equation :

(width + 181) + width = 515

2×width + 181 = 515

2×width = 334

width = 167 ft

because of

length = width + 181

length = 167 + 181 = 348 ft

Answer 2

The width and length of the rectangular field are 165.5 ft and 346.5 ft respectively.

Concept: Perimeter is the sum of the length of all sides of a figure/solid.

Given: Length = 181+width

Let width be equal to 'width' ft

Perimeter= 1030 feet

In a rectangle there are 2 length and 2 width so the perimeter of a rectangle is equal to 2*(181+ width) + 2width = 362 + 2width + 2 width = ⇒362 + 4width =1030 ft

4width = 662 ( on transposing)

width= 165.5 ft

length= 181+ 165.5 ft

length = 346.5 ft

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