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kumpel [21]
1 year ago
13

Solve for x -

la1" title="\bold{x {}^{2} - 25 + 16 = 0}" alt="\bold{x {}^{2} - 25 + 16 = 0}" align="absmiddle" class="latex-formula">

ty! ~​
Mathematics
2 answers:
Sladkaya [172]1 year ago
4 0

Hey!

Your equation is -

x {}^{2} - 25 + 16 = 0

x {}^{2} - 9 = 0

<u>We</u><u> </u><u>can</u><u> </u><u>write</u><u> </u><u>9</u><u> </u><u>as</u><u> </u><u>3</u><u>²</u><u> </u>(Why?) because it forms identity a² - b² = (a + b) (a - b) .

x {}^{2} -  {3}^{2}  = 0

(x - 3)(x + 3) = 0

This gives the information that either,

<u>x - 3 = 0 or x + 3 = </u><u>0</u>

<u>So</u><u>,</u><u> </u>x = 3 or x = -3

<em>Hope it helps,<u> you may ask if you have any </u><u>co</u></em>nfusions ^-^

12345 [234]1 year ago
3 0

<u>Answer:</u>

x = 3,   x = -3

<u>Step-by-step explanation:</u>

x² - 25 + 16 = 0

⇒ x² - 9 = 0

• Add 9 to both sides:

⇒ x² = 9

• Square root both sides of equation:

x = \sqrt{9}

x = ± 3

x = 3  and  x = -3

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