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Minchanka [31]
2 years ago
12

Find the value(s) of x in the function f(x) = |-2x – 3| when f(x) = 5. (Separate multiple answers with a comma.)

Mathematics
2 answers:
Ivan2 years ago
8 0

|-2x-3|=5\\-2x-3=5 \vee -2x-3=-5\\2x=-8 \vee 2x=2\\x=-4 \vee x=1\\\\\boxed{x\in\{-4,1\}}

diamong [38]2 years ago
6 0

Answer:

x = -4, 1

Step-by-step explanation:

Since we have a absolute value function here, we can tell there is goning to be multiple values.

First we will find x with the original function since we know |5| = 5.

Given f(x) = 5 = -2x-3,

2x-3 = 5 \\ -2x-3+3 = 5 + 3 \\ -2x = 8 \\ x = \frac{8}{ - 2}  \\  =  - 4

Now we also know that |-5| = 5 as well (absolute value)

Given |-2x-3| = |-5|,

- 2x  -  3 =  - 5 \\  - 2x  -  3  +  3 =  - 5 + 3\\  - 2x =  - 2 \\ x =  \frac{ - 2}{ - 2}  \\  =  1

You can verifiy these 2 values by substituting them into the equation.

f(-4) = |-2(-4)-3|

= |8-3|

= |5|

= 5

f(1) = |-2(1)-3|

= |-2-3|

= |-5|

= 5

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A parabola can be drawn given a focus of (3, 1) and a directrix of x = -5. What can
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Answer:

The statements that can be made about the parabola are;

The parabola opens towards the right

The equation of the parabola is (y - 1)² = 16 × (x + 1)

The parabola has a vertex at (-1, 1)

Step-by-step explanation:

The given focus of the parabola is (3, 1)

The directrix of the parabola, x = -5

Therefore, from the location of the directrix (on the x-axis) and the location of the focus relative to the directrix towards the positive direction of the x-axis relative to the directrix, the parabola opens towards the left of the coordinate chart

The general equation of the focus = (h + p, k)

The general equation of the directrix, x = h - p

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The equation of the parabola = (y - 1)² = 4 × 4 × (x - (-1))

(y - 1)² = 16 × (x - (-1))

The equation of the parabola is (y - 1)² = 16 × (x + 1).

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