If IK=JK, find mlJ A. 72° B. 82° C. 122° D. 134°

If A(3,4) and B(10,4) are the end points of a diameter of circle "O", what is the area of the circle O

ikadub [295]

Answer:

$\large\boxed{\dfrac{49\pi}{4}}$

Step-by-step explanation:

The formula of an area of a circle:

$A=\pi r^2$

r - radius

We have the endpoints of a diameter of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the given points A(3, 4) and B(10, 4):

$d=\sqrt{(10-3)^2+(4-4)^2}=\sqrt{7^2+0^2}=\sqrt{7^2}=7$

Therefore we have the length of the diameter: d = 7

We know: d = 2r. Therefore

$r=\dfrac{7}{2}$

Substitute to the formula of an area:

$A=\pi\left(\dfrac{7}{2}\right)^2=\dfrac{49\pi}{4}$

There is no such answer in the answers to choose.

Apparently you have some error in the coordinates of the endpoints.

8 0

3 years ago

What is the equation of the line given the table

OLEGan [10]

Answer:

y=3x-1

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean

ki77a [65]

Answer:

$P(Z>3) = 1-P(Z$

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu=?,\sigma=?)$

We are interested on this probability

$P(X>X+3\mu)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

And we can find the following probablity:

$P(Z>3) = 1-P(Z$

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0

3 years ago

9 3/4 - 1 1/4 in simplest form

Kipish [7]

8 1/2 would be the answer to this question

4 0

4 years ago

24-x/x = 1/2 find x please i need help

Aliun [14]

Answer:

No Solution

Step-by-step explanation:

There are no values of x that make the equation true.

3 0

3 years ago