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natulia [17]
2 years ago
7

Square root of x plus 8 end root minus 6 equals x

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
5 0

Answer:

Squaring both the sides, we get a quadratic and solving it, we find that the possible values of x are -7 and -4.

Step-by-step explanation:

The expression can be written as √(x+8) - 6 = x. Take 6 on the other side and square both the sides.

[√(x + 8)]² = (x + 6)²

x + 8 = x² + 12x + 36

x² + 11x + 28 = 0

x² + 7x + 4x + 28 = 0

(x + 7)(x + 4) = 0

x = -7 and x = -4

The possible values of x are -7 and -4.

For more explanation, refer the following link:

brainly.com/question/10572241

#SPJ10

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If f(x)=4x2=1 and g(x)=x2-5, find (f-g)(x)<br>A:3x2+6<br>B:5x2-6<br>C:3x2-4<br>D:5x2-4
Alex787 [66]

For this case we have the following functions:

f (x) = 4x ^ 2 + 1\\g (x) = x ^ 2-5

We must find(f-g) (x):

By definition of operations with functions we have:

(f-g) (x) = f (x) -g (x)

So:

(f-g) (x) = f (x) -g (x) = 4x ^ 2 + 1- (x ^ 2-5) = 4x ^ 2 + 1-x ^ 2 + 5 = 3x ^ 2 + 6

Answer:

Option A

3x ^ 2 + 6

5 0
4 years ago
Number 7. Please asap.
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7a)

\frac{n(n - 3)}{2} = 665\\n(n - 3) = 665 \cdot 2\\n(n - 3) = 1330\\n^2 - 3n = 1330\\n^2 - 3n - 1330 = 0\\n = \frac{-(-3) \pm \sqrt{(-3)^2 - 4 \cdot 1 \cdot (-1330)}}{2 \cdot 1} = \frac{3 \pm \sqrt{9 + 5320}}{2} = \frac{3 \pm \sqrt{5329}}{2} = \frac{3 \pm 73}{2}\\n_1 = \frac{3 + 73}{2} = \frac{76}{2} = 38\\n_2 = \frac{3 - 73}{2} = \frac{-70}{2} = -35

If n is the amount of sides then there's 38 sides in a polygon with 665 diagonals

7b)

We do the same as 7a) but with 406. We get that n_1 = 30.04 and n_2 = -27.04. A polygon cant have 30.04 sides

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