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Alex73 [517]
2 years ago
8

Aria paid $75,000 for her house. its property value increased by 2.2% per year. when aria sold her house after eleven years, how

much was it worth, to the nearest hundred dollars?a.$133,700b.$95,400c.$95,300d.$93,100 please select the best answer from the choices providedabcd
Mathematics
1 answer:
Wewaii [24]2 years ago
3 0

Answer:

D

Step-by-step explanation:

Converting percent to decimal : 2.2/100 = 0.022

Finding 2.2$ of $75k : 75,000 x 0.022 = $1,650 (also the increase in one year)

Finding how much it was worth after 11 years :

(75,000 x 0.022) x 11 = $18,150 or 1,650 x 11 = $18,150

Now add the product to the regular amount to find out the answer:

75,000 + 18,150 = $93,150 (which is how much it increased after 11 years)

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mel-nik [20]

Answer:35

Simplifying

5(x + 20) = 7x + 30

Reorder the terms:

5(20 + x) = 7x + 30

(20 * 5 + x * 5) = 7x + 30

(100 + 5x) = 7x + 30

Reorder the terms:

100 + 5x = 30 + 7x

Solving

100 + 5x = 30 + 7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.

100 + 5x + -7x = 30 + 7x + -7x

Combine like terms: 5x + -7x = -2x

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Combine like terms: 7x + -7x = 0

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Add '-100' to each side of the equation.

100 + -100 + -2x = 30 + -100

Combine like terms: 100 + -100 = 0

0 + -2x = 30 + -100

-2x = 30 + -100

Combine like terms: 30 + -100 = -70

-2x = -70

Divide each side by '-2'.

x = 35

Simplifying

x = 35

Hope it helps. Please tell me if im correct

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