Ask question

Ask question

All categories

2 years ago

12

Timothy is an hourly employee and he can work maximum of 40 hours in a week. If the weekly salary depends on the number of hours

(h) worked, what will be the domain of the function in this context?
a. h < 40, h ∈ Z
b. h ≥ 0, h ∈ R
c. 0 ≤ h ≤ 40, h ∈ R
d. h ≤ 40, h ∈ R

1 answer:

Gennadij [26K]2 years ago

7 0

Answer:

C

Step-by-step explanation:

0 ≤ h ≤ 40, h ∈ R

Hope this helps :)

You might be interested in

For the following system, use the second equation to make a substitution for why in the first equation. Will mark brainlyest!

Alona [7]

Answer:

b

Step-by-step explanation:

get y by itself in the second equation: y= 2x-3

substitute this into the y of the first equation:

2x+2x-3= 5

7 0

3 years ago

Use a calculator to find the standard deviation of this data set: 8, 14, 12, 9, 16

muminat

Answer : 23.6

<h3>Hope this help ;)</h3>

6 0

2 years ago

Read 2 more answers

How do you factor m^2=2m?<br><img src="https://tex.z-dn.net/?f=m%20%5E%7B2%7D%20%20%3D%202m" id="TexFormula1" title="m ^{2} = 2

Sonbull [250]

First move all terms to one side:

$m^2=2m\implies m^2-2m=0$

Then all terms on the left side share a common factor of $m$ :

$m(m-2)=0$

The zero product product property says that if $ab=0$ , then $a=0$ or $b=0$ . So either $m=0$ or $m-2=0\implies m=2$ .

5 0

3 years ago

For each expression listed, is it a difference of squares? Explain yes or no and why or why not. Explain in enough detail so the

Harlamova29_29 [7]

<h2>Explanation:</h2><h2></h2>

If we can write a polynomial in the form $a^2-b^2$ , then we can factor it as:

$a^2-b^2=(a-b)(a+b)$

In this problem, we have the following expressions:

$1. \ y^5 - 25 \\ \\ 2. \ 9m^2n^2-121 \\ \\ 3. p^{18} - q^{10} \\ \\ 4. 16r^2 - 27$

For 1 and 4 we can't write this in the form $a^2-b^2$ so this is not a difference of squares.

For 2:

$9m^2n^2-121 =3^2m^2n^2-11^2 \\ \\ =(3mn)^2-11^2 =(3mn-11)(3mn+11)$

So we could write 2 as a difference of squares.

For 3:

$p^{18} - q^{10}=(p^9)^2-(q^5)^2=(p^9-q^5)(p^9+q^5) \\ \\ \\ Remember: \ (a^m)^n=a^{mn}$

So we could write 2 as a difference of squares.

7 0

3 years ago

rewona [7]

Part B - Question 1

Distance for the spacecraft to travel from Venus to Jupiter = Distance of Jupiter from Sun - Distance of Venus from Sun

⇒ Distance for the spacecraft to travel from Venus to Jupiter = 4.838 × 10⁸ - 6.724 × 10⁷

⇒ Distance for the spacecraft to travel from Venus to Jupiter = 483,800,000 - 67,240,000

⇒ Distance for the spacecraft to travel from Venus to Jupiter = 416,560,000

⇒ Distance for the spacecraft to travel from Venus to Jupiter = 4.1656 × 10⁸

Part B - Question 2

Combined distance of Mercury, Venus, and Earth from the Sun = Distance of Mercury from Sun + Distance of Venus from Sun + Distance of Earth from Sun

⇒ Combined distance of Mercury, Venus, and Earth from the Sun = 5.7909 × 10⁷ + 6.724 × 10⁷ + 9.296 × 10⁷

⇒ Combined distance of Mercury, Venus, and Earth from the Sun = 21.8109 × 10⁷

⇒ Combined distance of Mercury, Venus, and Earth from the Sun = 2.18109 × 10⁸

Distance of Neptune from the Sun = 2.793 × 10⁹

Hence, we can see that the combined distance of Mercury, Venus and Earth from the Sun is <u>less</u> than that of Neptune from the Sun.

Part B - Question 3

If Earth was 10 times farther away from the sun, then the new distance between the Sun and the Earth = 10 × 9.296 × 10⁷

⇒ New distance between the Sun and the Earth = 9.296 × 10⁸

Now, the Earth will be closest to Saturn, which is 8.907 × 10⁸ away from the Sun

New Distance between Earth and Saturn = Distance of Earth from Sun - Distance of Saturn from Sun

⇒ New Distance between Earth and Saturn = 9.296 × 10⁸ - 8.907 × 10⁸

⇒ New Distance between Earth and Saturn = 0.389 × 10⁸

⇒ New Distance between Earth and Saturn = 3.89 × 10⁷ (in scientific notation)

⇒ New Distance between Earth and Saturn = 38,900,000 (in standard notation)

Part B - Question 4

Speed of space shuttle = 28,000 km per hour

Time spent to travel from Saturn to Earth = $\frac{\text{Distance between Saturn and Earth}}{\text{Speed of space shuttle} }$

⇒Time spent to travel from Saturn to Earth = $\frac{\text{Distance of Saturn from Sun - Distance of Earth from Sun}}{\text{Speed of space shuttle} }$

⇒Time spent to travel from Saturn to Earth = $\frac{8.907 * 10^8 - 9.296 * 10^7}{28,000}$

⇒Time spent to travel from Saturn to Earth = $\frac{797,740,000 }{28,000}$

⇒Time spent to travel from Saturn to Earth = 28,490.7 hours

⇒Time spent to travel from Saturn to Earth = 28,491 hours

Hence, it will take 28,491 hours or 2.8491 x 10⁵ hours for the space shuttle to travel from Saturn to Earth.

3 0

2 years ago

Read 2 more answers