What is the percent by mass of 5 g of sodium chloride mixed with 80 g of water
1 answer:
Answer:
mass of solute (m1) = 5.0 g NaCl
mass of solvent (m2 ) = 80.0 g H2O
T% = ( m1 / m1 + m2 ) * 100
T% = ( 5.0 / 5.0 + 80.0 ) * 100
T% = ( 5.0 / 85.0 ) * 100
T% = 0.0588 * 100
T = 5.88%
Explanation:
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