All categories

2 years ago

The surface area of a sphere is 6477 square inches. Which equation can be used to solve for the radius of the

Mathematics

1 answer:

Vinil7 [7]2 years ago

3 0

The expression πr² = 6477 can be used to solve for the radius of the sphere.

<h3>What is a sphere?</h3>

It is defined as three-dimensional geometry when half-circle two-dimensional geometry is revolved around the diameter of the sphere that will form.

$\rm V = \dfrac{4}{3} \pi r^3$

Area of sphere A = 6477 square inches

A = 4πr²

A = 6477

4πr² = 6477

πr² = 6477

Thus, the expression πr² = 6477 can be used to solve for the radius of the sphere.

Learn more about the sphere here:

brainly.com/question/11374994

#SPJ1

You might be interested in

A cup of cereal has 1212 grams of fiber, which is 40%40% of the recommended daily allowance. What is the recommended daily amoun

Cloud [144]

30 grams
40% + 40% + 20% = 100%
12 + 12 + 6 = 30

4 0

4 years ago

The force exerted by an electric charge at the origin on a charged particle at a point (x, y, z) with position vector r = x, y,

suter [353]

Answer:

$\frac{25k}{34}[\frac{1}{4}-\frac{1}{50^{1/2}}] \\$

Step-by-step explanation:

The straight line path between point (a,b,c) and (l,m,n) is parametric by the expression

$r(t)=(1-t)(a,b,c) +t(l,m,n)\\$

since we are giving point (4,0,0) and (4,3,4), the parametric equation is giving below

$r(t)=(1-t)(4,0,0) +t(4,3,4)\\$

using the dot product system of multiplication, we have

$r(t)=(4,3t,4t) \\$

t is between 0,1.

Next we define the line integral for work done which is express as

$\int\limits^a_b {F.} \,dr\\$

First we define the general expression for the force

$f(x,y,z)=\frac{K(x,y,z)}{(x^{2}+y^{2}+z^{2})^{3/2}} \\$

If we substitute our parametric equation we arrive at

$F(r(t))=\frac{K(4,3t,4t)}{(4^{2}+(3t)^{2}+(4t)^{2})^{3/2}}\\F(r(t))=\frac{K(4,3t,4t)}{(16+34t^{2})^{3/2}}\\$

also we need to find the expression for <em>dr</em>

$r(t)=(4,3t,4t)\\dr=(0,3,4)dt\\$

Now we substitute into the integral expression

$\int\limits^1_0 {\frac{k(4,3t,4t)}{(16+34t^{2})^{3/2}}} \, .(0,3,4)dt$

using dot product we arrive at

$\int\limits^1_0 {\frac{25kt}{{(16+34t^{2})^{3/2}} } \,$

let make a simple substitution so we can simplify the integral,

let assume $u=16+34t^{2}\\$

$\frac{du}{dt}=68t\\ dt=\frac{du}{68t} \\$

and changing setting the new upper and lower limit, we have

$\frac{25k}{68} \int\limits^a_b {\frac{1}{u\frac{3}{2} } } \, du\\a=50\\b=16\\$

by simple integral we arrive at

$-\frac{25k}{34}[\frac{1}{u^{1/2}}] ^{50}_{16} \\\frac{25k}{34}[\frac{1}{4}-\frac{1}{50^{1/2}}] \\$

Hence the workdone is

$\frac{25k}{34}[\frac{1}{4}-\frac{1}{50^{1/2}}] \\$

3 0

3 years ago

A stone is an English measure of weight. There are 14 lb in 1 stone and 2.2 lb in 1 kg. A certain person weighs 9 stone.

USPshnik [31]

For every one stone it's 14lb and for every kg it's 2.2 lb therefore you would have to multiply 14 by 9 then divide that answer by 2.2 and that answer will be your answer..
14•9=126
126÷2.2=57.27
You would have 57.27kg or if rounded you would have 57kg
Hope this helps

8 0

4 years ago

patrick prepared 12 kg of dough after working 3 hours how much dough did Patrick prepare if he worked for 5 hours

enyata [817]

Answer:

20 kg

Step-by-step explanation:

12/3 = 4

4 x 2 = 8

12 + 8 = 20

4 0

4 years ago