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larisa86 [58]
1 year ago
6

The graph shows a relationship between x and y. What are the zeros of the function?

Mathematics
1 answer:
miv72 [106K]1 year ago
8 0

Answer:

x = -3

x = -1

x = 2

Step-by-step explanation:

The <u>zeros of a function</u> are the x-values of the points at which the curve crosses the x-axis.

From inspection of the given graph, the curve crosses the x-axis at:

  • x = -3
  • x = -1
  • x = 2

Therefore, these are the zeros of the function.

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I can't figure this question out I've tried multiple times but only 2/3. Help, please.
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Answer:

yes it is 2/3

Step-by-step explanation:

4 0
3 years ago
Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
2 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

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Answer:

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2 years ago
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ejdencrejnoqnf3enrn3nf god is greatttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttt

Step-by-step explanation:

4 0
3 years ago
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