Answer:
a = 39.2650873379cm
b = 11.5529459767cm
Step-by-step explanation:
a - Use the area of a triangle equation - 1/2 * a * b * Sin(C)
1/2 * 8 * 10 * Sin(79) = 39.2650873379cm
b - Use the cosine rule - c^2 = a^2 + b^2 - (2 * a * b * Sin(C)
64 + 100 - (2 * 8 * 10 * Cos(79)) = 133.4705607398
c = square root of 6.9396506484 = 11.5529459767cm
Put to however many significant figures / decimal places required.
:)
the answer is A but im just guessing ya know?
Answer:

Step-by-step explanation:
we know that

Remember the identity

step 1
Find the value of 
we have that
The angle alpha lie on the III Quadrant
so
The values of sine and cosine are negative

Find the value of sine

substitute




step 2
Find the value of 
we have that
The angle beta lie on the IV Quadrant
so
The value of the cosine is positive and the value of the sine is negative

Find the value of cosine

substitute




step 3
Find cos (α + β)

we have




substitute



Answer: It will take it 3 seconds before getting to the chicken
Use the formula of the future value of annuity ordinary and solve for pmt
First deducted the amount of down payment
184,500−184,500×0.20=147,600
Pmt=147,600÷(((1+0.085
÷12)^(12×10)−1)÷(0.085÷12))
=784.53 per month