Answer:
0.65
Step-by-step explanation:
Given equation:
P = 0.65n
where,
P = price
n = number of pears
What is the constant of proportionality?
The constant of proportionality is 0.65
For example
Find P when n = 2
P = 0.65n
= 0.65(2)
P = 1.3
Answer:
Earning at Long's Bank are expressed by the equation, I = -0.06 x + 8.3
Earnings at Fellow's Bank are modeled by I = -0.02 x+6.6
Where,x is the number of checks written.
now, we have to find that , at what range of checks will a checking account at Long's Bank generate more earnings income than one at Fellow's Bank.
-0.06 x +8.3 > -0.02 x +6.6
-0.02 x+0.06 x < 8.3 - 6.6
0.04 x < 1.7
Dividing both sides by , 0.04, we get
x< 42.5
So, x ∈[0,42], which is number of checks written.
2. APR on personal Loans =5.5%
Value of APR when compounded monthly

=0.46 (approx)
Value of APR when compounded Quarterly

= 1.84 (approx)
Difference between Rate , when the APR rate is compounded monthly as compared to when it's compounded quarterly
=1.84 - 0.46
=1.38 (approx)
Quarterly APR is 1.38 value more than Monthly APR, when the rate of Yearly APR is 5.5%.
Answer:
You can plug in the simple interest formula A=P(1+rt) to get the amount is equal to 3500 (the principal in this case) times 1+ 3.49/100(10). This is 3500(1.349), and this is $4721.5.
Answer:
See explanation
Step-by-step explanation:
You have to graph the system of inequalities presented as

Part A:
1. Draw a dotted line
(dotted because the sign < is without notion "or equal to"). Select one of two regions by substituting the coordinates of origin into inequality:

Since this inequlity is false, the origin doesn't belong to the shaded region, so you have to shade that part which doesn't contain origin (red part in attached diagram).
2. Draw a solid line
(solid because the sign ≥ is with notion "or equal to"). Select one of two regions by substituting the coordinates of origin into inequality:

Since this inequlity is true, the origin belongs to the shaded region, so you have to shade that part which contains origin (blue part in attached diagram).
The intersection of these two regions is the solution area.
Part B:
Plot point (-2,-2). Since this point doesn't belong to the solution area, this is not a solution of the system of two inequalities. You can check it mathematically - substitute x=-2 and y=-2 into the system:

Both inequalities are false, so (-2,-2) doesn't belong to the solution area.