Question

What is the value of:

Answer 1

Step-by-step explanation:

$\log(x) = - 1$

$\log(y) = 6$

$\log(z) = 2$

$\:$

$= \log( \frac{ {x}^{3}y }{ {z}^{2} } )$

$= \log( {x}^{3} \times y \div {z}^{2} )$

$= \log( {x}^{3} ) + \log(y) - \log( {z}^{2} )$

$= 3 \log(x) + \log(y) - 2 \log(z)$

$= 3.( - 1) + 6 - 2$

$= - 3 + 6 - 2$

$= 1$