Ask question

Ask question

All categories

3 years ago

8

What is the probability of having an odd number in a single toss of a fair die?

1 answer:

mel-nik [20]3 years ago

7 0

If I'm not mistaken, the correct answer would be the probability is 3/6 or 1/2. Hope this helps :D

You might be interested in

Penelope has $1,459.75 in her bank account. To pay her bills, she writes 4 checks for $200.25, $359.45, $125, and $299.35. Then

Sophie [7]

I subtracted 375 not added

8 0

3 years ago

Read 2 more answers

Simplify the rational expression. State any restrictions on the variable.

AveGali [126]

Answer:

The last choice.

Step-by-step explanation:

$\dfrac{k^2-k-2}{k^2-4k-5}=\dfrac{(k+1)(k-2)}{(k+1)(k-5)}=\dfrac{k-2}{k-5}$

The value of k must be restricted from being one that makes the original denominator zero. Hence k ≠ -1 or 5.

7 0

3 years ago

I don't know how to do this (answer pls ) number 3

Blababa [14]

Subtract 2b by both sides which gets -b+4=-5 then subtract 4 by both sides so you get -b=-9 and divide -1 by both sides so that b=9

5 0

3 years ago

Read 2 more answers

Give an example of a compound inequality that has no solution

Vladimir79 [104]

-3 < x < -8

There is no value of c that is greater than -3 AND less that -8

3 0

3 years ago

find the mean, median, and mode of the data set round to the nearest tenth 15, 1 , 4, 4, 8, 7, 15, 4, 5

Dmitriy789 [7]

$15,\ 1,\ 4,\ 4,\ 8,\ 7,\ 15,\ 4,\ 15,\ 4,\ 5\to\underbrace{1,\ 4,\ 4,\ 4,\ 4,\ 5,\ 7,\ 8,\ 15,\ 15,\ 15}_{11}\\\\mean=\dfrac{1+4+4+4+4+5+7+8+15+15+15}{11}=\dfrac{82}{11}\approx7.5\\\\median:1,\ 4,\ 4,\ 4,\ 4,\ \boxed{5},\ 7,\ 8,\ 15,\ 15,\ 15\\\\mode:1,\ \underbrace{4,\ 4,\ 4,\ 4}_{4},\ 5,\ 7,\ 8,\ 15,\ 15,\ 15$

<h3>Answer: mean = 7.5, median = 5, mode = 4</h3>

6 0

3 years ago

Read 2 more answers