The answer to the question is A
The price of a staff ticket and the price of a student ticket is $8 and $14
Given:
Day 1:
Number of staff tickets sold = 3
Number of students tickets sold = 1
Total revenue day 1 = $38
Day 2:
<em>Number of staff tickets sold</em> = 3
<em>Number of students tickets sold</em> = 2
<em>Total revenue day</em> 2 = $52
let
<em>cost of staff tickets</em> = x
<em>cost of students tickets</em> = y
The equation:
<em>3x + y = 38 (1)</em>
<em>3x + y = 38 (1)3x + 2y = 52 (2)</em>
subtract (1) from (2)
2y - y = 52 - 38
y = 14
substitute y = 14 into (1)
3x + y = 38 (1)
3x + 14 = 38
3x = 38 - 14
3x = 24
x = 24/3
x = 8
Therefore,
cost of staff tickets = x
= $8
cost of students tickets = y
= $14
Read more:
brainly.com/question/22940808
Okay, it's wrong because they forgot to do -2 times 3x.
The correct answer is
-2x-8
Hope i got is correct!
Answer:
$39.60
Step-by-step explanation:
We are finding 66 - 40%
66 less 40% = 60% of 66
60% of 66 is the price of the item now.
Convert 60% to decimal form by dividing by 100.
60%/100 = 0.60
Multiply the decimal form by 66
66 X 0.6 = 39.60
Since we are dealing with money, keep 2 decimal places, even if the last digit is 0.
The price of the item now is $39.60.
